By John H. Lienhard IV and John H. Lienhard V
This textbook is an advent to warmth and mass move orientated towards engineering scholars. the themes coated comprise warmth conduction, pressured and usual convection, thermal radiation, boiling, condensation, warmth exchangers, and mass move. The booklet contains labored examples and end-of-chapter routines. The 3rd variation (2003) has been greatly revised and up to date from the previous moment version (1987).
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Extra info for A Heat Transfer Textbook, Third Edition
What fraction of the heat transfer from the bulb is by radiation directly from the ﬁlament through the glass? 31 produce? 6 W/m2 K). Methanol at 87◦ C ﬂows over the other side (h = 141 W/m2 K). The metal functions as an electrical resistance heater, releasing 1000 W/m2 . Calculate (a) the heater temperature, (b) the heat transfer from the methanol to the heater, and (c) the heat transfer from the heater to the air. 6 W/m2 K) and by radiation to a parallel black wall at 80◦ C. What is the temperature of the ﬁrst wall if it delivers 9000 W/m2 .
24 will give a positive ∆S whether Tb > T∞ or Tb < T∞ because the sign of dTb will always opposed the sign of the integrand. 4 A thermocouple bead is largely solder, 1 mm in diameter. It is initially at room temperature and is suddenly placed in a 200◦ C gas ﬂow. 18 kJ/kg·K, respectively. Evaluate the response of the thermocouple. 3 Solution. 116 s = ρcV = Therefore, eqn. 116 ◦ C (20 − 200)◦ C This result is plotted in Fig. 12, where we see that, for all practical purposes, this thermocouple catches up with the gas stream in less than 5 s.
This condition must be satisﬁed or the lumped-capacity solution will not be accurate. We call the group hL kb the Biot number 6 , Bi. If Bi were large, of course, the situation would be reversed, as shown in Fig. 11. In this 1 and the convection process oﬀers little resistance case Bi = hL/kb to heat transfer. We could solve the heat diﬀusion equation 1 ∂T ∂2T = 2 α ∂t ∂x subject to the simple boundary condition T (x, t) = T∞ when x = L, to determine the temperature in the body and its rate of cooling in this case.